Man in an Accelerating Lift – Rankers Physics

Pseudo Force: Practice Problem & Solution

Assertion (A): A man standing in a lift which is moving upward, will feel his weight to be greater than when the lift was at rest. Reason (R): If the acceleration of the lift is 'a' upward, then the man of mass m shall feel his weight to be equal to normal reaction (N) exerted by the lift given by \(N = m(g - a)\) (where \(g\) is acceleration due to gravity)  
(1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
(2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(3) (A) is true but (R) is false
(4) Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Pseudo Force. Understanding the underlying formula is key to arriving at the correct answer below:

When a lift accelerates upwards, apparent weight is \(N = m(g + a)\), which is greater than \(mg\). So (A) is true. Reason (R) provides the formula for downward acceleration, thus (R) is false.

Leave a Reply

Your email address will not be published. Required fields are marked *