Linear Momentum and Second Law of Motion: Practice Problem & Solution
A hammer of man 1 kg moving with a speed of 6 m/sec strikes a wall and comes to rest in 0.1 sec find average retarding force that stops the hammer :
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Linear Momentum and Second Law of Motion. Understanding the underlying formula is key to arriving at the correct answer below:
According to Newtons second law of motion, Force is time rate of change in momentum.
So, F = change in momentum / time
F= m (vf-vi)/t= 1 kg (0-6)/0.1= -60 N
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