Definition of Force Inertia and First Law: Practice Problem & Solution
A 1 kg object strikes a wall with velocity \(1 \text{ms}^{-1}\) at an angle of \(60^\circ\) with the wall and reflects at the same angle. If it remains in contact with wall for 0.1 s, then the force exerted on the wall is
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Definition of Force Inertia and First Law. Understanding the underlying formula is key to arriving at the correct answer below:
The component of velocity perpendicular to the wall is \(v_n = v sin 60^\circ = \frac{\sqrt{3}}{2} \text{m/s}\). The change in momentum is \(\Delta p = 2 m v_n = 2 \times 1 \times \frac{\sqrt{3}}{2} = \sqrt{3} \text{kg m/s}\). The force is \(F = \frac{\Delta p}{\Delta t} = \frac{\sqrt{3}}{0.1} = 10\sqrt{3} \text{N}\).
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