Mechanical Energy of Earth-Moon System – Rankers Physics

Planet and Satellite: Practice Problem & Solution

Assertion (A): The mechanical energy of earth-moon system remains same when another heavenly body passes nearby the earth-moon system. Reason (R): Force exerted by heavenly body on the earth-moon system is non-conservative.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Planet and Satellite. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is false.

If another heavenly body passes nearby, it exerts an external gravitational force on the earth-moon system. This external force can do work, changing the system's total mechanical energy.

Reason (R) is false. Gravitational force is a conservative force, not non-conservative. Therefore, both (A) and (R) are false.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. The gravitational force of attraction between two bodies is \(F\) newtons. If the mass of each body and the distance between them are doubled, then the gravitational force between them in newton is
2. If the earth stops rotating about its axis, the acceleration due to gravity will remain unchanged at
3. The acceleration due to gravity increases by \(0.5\%\) when we go from the equator to the poles. What will be the time period of the pendulum at the equator which beats seconds at the poles?
4. What is the increase in gravitational potential energy of an object of mass m raised from the surface of earth to a height equal to n times of earth radius ?
5. The escape velocity from earth is $11.2\text{ km/s}$. If a body is to be projected in a direction making an angle $45^{\circ}$ to the vertical, then the escape velocity is: (1993)