Gravitational Force at Centroid – Rankers Physics

Newton's Law of Gravitation: Practice Problem & Solution

Three equal masses of \(3\text{ kg}\) each are fixed at the vertices of an equilateral triangle ABC. The gravitational force acting on mass \(2\text{ kg}\) placed at the centroid of triangle is
Zero
\(6.67 * 10^{-3}\) N
\(9 * 10^{-9}\) N
Data is insufficient

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Newton's Law of Gravitation. Understanding the underlying formula is key to arriving at the correct answer below:

Due to perfect symmetric distribution, the three gravitational pull forces on the mass at the centroid are equal in magnitude and separated by \(120^circ\), resulting in a net vector sum of zero.

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