Rankers Physics

Acceleration Due to Gravity and its variation: Practice Problem & Solution

The depth at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R be the radius of the earth) :
R/n
R/n²
R(n-1)/n
Rn/n-1

Solution Explained:

To solve this problem, we apply the core principles of Acceleration Due to Gravity and its variation. Understanding the underlying formula is key to arriving at the correct answer below:

The depth at which the acceleration due to gravity becomes \( \frac{1}{n} \) times the surface value is:

\[
d = \left( 1 - \frac{1}{n} \right) R
\]

where \( R \) is the radius of the Earth.

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