Rankers Physics

Gravitational Potential Energy: Practice Problem & Solution

The escape velocity of a body on the surface of the earth is $11.2\text{ km/s}$. If the earth's mass increases to twice its present value and radius of the earth becomes half, the escape velocity becomes: (1997)
$22.4\text{ km/s}$
$44.8\text{ km/s}$
$5.6\text{ km/s}$
$11.2\text{ km/s}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Gravitational Potential Energy. Understanding the underlying formula is key to arriving at the correct answer below:

Escape velocity is given by $v_e = \sqrt{\frac{2GM}{R}}$. When mass becomes $2M$ and radius becomes $R/2$, $v'_e = \sqrt{\frac{2G(2M)}{R/2}} = 2v_e$. Thus, $v'_e = 2 \times 11.2\text{ km/s} = 22.4\text{ km/s}$.

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