Gravitational Potential Energy: Practice Problem & Solution
The escape velocity of a body on the surface of the earth is $11.2\text{ km/s}$. If the earth's mass increases to twice its present value and radius of the earth becomes half, the escape velocity becomes: (1997)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Gravitational Potential Energy. Understanding the underlying formula is key to arriving at the correct answer below:
Escape velocity is given by $v_e = \sqrt{\frac{2GM}{R}}$. When mass becomes $2M$ and radius becomes $R/2$, $v'_e = \sqrt{\frac{2G(2M)}{R/2}} = 2v_e$. Thus, $v'_e = 2 \times 11.2\text{ km/s} = 22.4\text{ km/s}$.
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