Electric Potential: Practice Problem & Solution
Sixty four identical drops of water having equal charge combine to form a bigger drop. The factor by which potential of bigger drop change in comparison to a small drop is
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Electric Potential. Understanding the underlying formula is key to arriving at the correct answer below:
By conserving volume, \(R = n^{1/3}r = 64^{1/3}r = 4r\). The total charge is \(Q = 64q\). Thus, potential of the big drop is \(V' = \frac{kQ}{R} = \frac{64kq}{4r} = 16V\).
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