Rankers Physics

Electric Potential: Practice Problem & Solution

Figure shows three circular arcs, each of radius R and total charge as indicated. The net electric potential at the centre of curvature is :   Electric Potential diagram: Figure shows three circular arcs, each of radius
\[\frac{Q}{2\pi \varepsilon_{0}R}\]
\[\frac{Q}{4\pi \varepsilon_{0}R}\]
\[\frac{2Q}{\pi \varepsilon_{0}R}\]
\[\frac{Q}{\pi \varepsilon_{0}R}\]

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Electric Potential. Understanding the underlying formula is key to arriving at the correct answer below:

As potential is a scaler quantity distribution of charges will not have any effect.

Total charge = 3Q-2Q+Q= 2Q

Electric Potential V = \( \frac{2KQ}{R}= \frac{Q}{2\pi \varepsilon_{0}R}\)

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