Electric Flux through Cube Face – Rankers Physics

Electric Flux: Practice Problem & Solution

A charge \(Q\) \(mu\text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit)
\(\frac{Q}{6ε_0} times 10^{-3}\)
\( \frac{Q}{6ε_0} times 10^{-6}\)
\( \frac{Q}{ε_0} times 10^{-6}\)
\( \frac{2Q}{3ε_0} times 10^{-3}\)

Solution Explained:

To solve this problem, we apply the core principles of Electric Flux. Understanding the underlying formula is key to arriving at the correct answer below:

By Gauss's law, the total flux through the cube is \(\Phi = \frac{q_{\text{enclosed}}}{ε_0}\). Since the charge is at the center, the flux through one of the six faces is \(\Phi_1 = \frac{\Phi}{6} = \frac{Q \times 10^{-6}}{6ε_0}\).

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