Rankers Physics

Electric Flux: Practice Problem & Solution

Two point charge, each of q, are kept at centre of cube O and vertex A. Find \[\phi_{e}\] from shaded face. Electric Flux diagram: Two point charge, each of q, are kept
\[\frac{5q}{8\epsilon_{0}}\]
\[\frac{7}{24}\frac{q}{\epsilon_{0}}\]
\[\frac{2q}{\epsilon_{0}}\]
\[\frac{5}{24}\frac{q}{\epsilon_{0}}\]

Solution Explained:

To solve this problem, we apply the core principles of Electric Flux. Understanding the underlying formula is key to arriving at the correct answer below:

\phi= \frac{q}{6\varepsilon_{0}} + \frac{q}{24\varepsilon_{0}}= \frac{5q}{24\varepsilon_{0}}

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Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Consider the situation shown in figure. A point charge q is placed at a depth h= √3R exactly below the centre of mouth of a vessel whose open end is circular having a radius R. Calculate the electric flux through the lateral surface of this vessel.
2. The length of each side of a cubical closed surface is l. If charge q is situated on one of the vertices of the cube, then find the flux passing through shaded face of the cube.
3. The electric field components in the given figure are \(  E_{x}=\alpha x^{1/2}, E_{y}=E_{z}=0 \) in which \( \alpha=800NC^{-1}m^{-1/2}.\) The charge within the cube is if net flux through the cube is 1.05 N m²C–¹ (assume a = 0.1 m)  
4. In a certain region of surface there exists a uniform electric field of \( 2\times 10^{3}\hat{k} \) V/m. A rectangular coil of dimensions 10 cm × 20 cm is placed in x-y plane. The electric flux through the coil is 
5. Which of the following is sufficient condition for finding the electric flux Φ through a closed surface?