Gauss's Law: Practice Problem & Solution
The electric field at a point on the equatorial plane at a distance $r$ from the centre of a dipole having dipole moment $\vec{p}$ is given by, ($r \gg$ separation of two charges forming the dipole, $\epsilon_0$ - permittivity of free space) (2020-Covid)
Solution Explained:
To solve this problem, we apply the core principles of Gauss's Law. Understanding the underlying formula is key to arriving at the correct answer below:
The electric field at a point on the equatorial plane of a dipole is opposite to the dipole moment direction. Its magnitude is $E = \frac{p}{4\pi\epsilon_0 r^3}$. Thus in vector form, $\vec{E} = -\frac{\vec{p}}{4\pi \epsilon_0 r^3}$.
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