Properties of EM Waves: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Properties of EM Waves. Understanding the underlying formula is key to arriving at the correct answer below:

The wavelength associated with $15 keV$ is $\lambda = \frac{hc}{E} = \frac{1240 eV\cdot nm}{15 \times 10^3 eV} \approx 0.08 nm$ . A wavelength of $0.08 nm$ (or $0.8 \mathring{A}$ ) falls squarely in the X-ray region of the electromagnetic spectrum.