Properties of EM Waves: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Properties of EM Waves. Understanding the underlying formula is key to arriving at the correct answer below:

Comparing the given equation with the standard wave equation $B = B_0 \sin(kx + \omega t)$, we get the wave number $k = \pi \times 10^3 m^{-1}$.
The wavelength is related to the wave number by $\lambda = \frac{2\pi}{k}$.
Substituting $k$, we get $\lambda = \frac{2\pi}{\pi \times 10^3} = 2 \times 10^{-3} m$.