Rankers Physics

Motional EMF: Practice Problem & Solution

A copper rod AB of length L, pivoted at one end A, rotates at constant angular velocity ω, at right angles to a uniform magnetic field of induction B. The e.m.f developed between the mid point C of the rod and end B is : Motional EMF diagram: A copper rod AB of length L, pivoted
\[\frac{B\omega l^{2}}{4}\]
\[\frac{B\omega l^{2}}{2}\]
\[\frac{3B\omega l^{2}}{4}\]
\[\frac{3B\omega l^{2}}{8}\]

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