Rankers Physics

Motional EMF: Practice Problem & Solution

A conducting rod AC of length 4l is rotated about a point O in a uniform magnetic field B directed into the paper AO = l and OC = 3l. Then :- Motional EMF diagram: A conducting rod AC of length 4l is
\[V_{A}-V_{0}=\frac{B\omega l^{2}}{2}\]
\[V_{0}-V_{C}=\frac{7}{2}B\omega l^{2}\]
\[V_{A}-V_{C}=4 B\omega l^{2}\]
\[V_{C}-V_{0}=\frac{9}{2}B\omega l^{2}\]

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