Induced Electric Field Nature – Rankers Physics

Mutual Induction: Practice Problem & Solution

Assertion (A): An emf is induced in a closed loop where magnetic flux is varied. The induced electric field is not a conservative field. Reason (R): For induced electric field, the line integral \( \oint \vec{E} \cdot d\vec{l} \) around a closed path is non-zero.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Mutual Induction. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true because varying magnetic flux induces a non-conservative electric field. Reason (R) is true; for a non-conservative field, \( \oint \vec{E} \cdot d\vec{l} \neq 0 \). (R) correctly explains why the induced electric field is non-conservative.

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Similar Practice Questions

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1. Two circular coils one of small radius \(r\) and other of larger radius \(R\) (\(r \ll R\)) are placed co-axially with centres coinciding. The mutual inductance of the arrangement is
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