Rankers Physics

Faraday's Law of Electromagnetic Induction: Practice Problem & Solution

A rectangular coil ABCD is rotated anticlockwise with a uniform angular velocity about the axis shown in diagram below. The axis of rotation of the coil as well as the magnetic field B are horizontal. The induced e.m.f. in the coil would be maximum when Faraday's Law of Electromagnetic Induction diagram: A rectangular coil ABCD is rotated anticlockwise with
The plane of the coil is horizontal
The plane of the coil makes an angle of 45° with the magnetic field
The plane of the coil is at right angles to the magnetic field
The plane of the coil makes an angle of 30° with the magnetic field

No solution provided for this question.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. An equilaterial triangular loop having a resistance R and length of each side 'l' is placed in a magnetic field which is varying at dB/dt =1 T/s. The induced current in the loop will be :
2. A coil has a self-inductance of 0.02 H. The current through it, is allowed to change at the rate of 4 A in \(2 \times 10^{-2}\text{ s}\). The e.m.f induced in the coil will be
3. Assertion (A): The electric field created by time-varying magnetic field is non-conservative. Reason (R): The line integral of induced electric field in a closed loop is always equal to zero.
4. Assertion (A): At the instant when magnetic flux is zero, emf induced in the coil is maximum when it is rotating in uniform magnetic field w.r.t. axis in the plane of coil. Reason (R): emf induced in the coil is equal to rate of change of magnetic flux.  
5. Two coils have mutual inductance \(0.005\text{ H}\). The current changes in the first coil according to equation \(I = I_0 \sin \omega t\), where \(I_0 = 10\text{ A}\) and \(\omega = 100\pi\text{ rad/s}\). The maximum value of EMF in the second coil is: