Rankers Physics

Measuring Devices ( Galvanometer, Voltmeter and Ammeter & Meter Bridge ): Practice Problem & Solution

The resistance of an ammeter is $13 \Omega$ and its scale is graduated for a current upto $100 \text{ amps}$. After an additional shunt has been connected to this ammeter, it becomes possible to measure currents upto $750 \text{ amperes}$ by this meter. The value of shunt resistance is : (2007)
$2 \Omega$
$0.2 \Omega$
$2k \Omega$
$20 \Omega$

Solution Explained:

To solve this problem, we apply the core principles of Measuring Devices ( Galvanometer, Voltmeter and Ammeter & Meter Bridge ). Understanding the underlying formula is key to arriving at the correct answer below:

The shunt resistance is calculated as $S = \frac{I_g G}{I - I_g} = \frac{100 \times 13}{750 - 100} = \frac{1300}{650} = 2 \Omega$.

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