Rankers Physics

Power of Electrical Circuit: Practice Problem & Solution

If voltage across a bulb rated $220\text{ Volt} - 100\text{ Watt}$ drops by $2.5\%$ of its rated value, the percentage of the rated value by which the power would decrease is: (2012 Pre)
$20\%$
$2.5\%$
$5\%$
$10\%$

Solution Explained:

To solve this problem, we apply the core principles of Power of Electrical Circuit. Understanding the underlying formula is key to arriving at the correct answer below:

Power is given by $P = \frac{V^2}{R}$. For small changes, the fractional change is $\frac{\Delta P}{P} = 2\frac{\Delta V}{V}$. The percentage decrease in power will be $2 \times 2.5\% = 5\%$.

Leave a Reply

Your email address will not be published. Required fields are marked *