Power of Electrical Circuit: Practice Problem & Solution
If voltage across a bulb rated $220\text{ Volt} - 100\text{ Watt}$ drops by $2.5\%$ of its rated value, the percentage of the rated value by which the power would decrease is: (2012 Pre)
Solution Explained:
To solve this problem, we apply the core principles of Power of Electrical Circuit. Understanding the underlying formula is key to arriving at the correct answer below:
Power is given by $P = \frac{V^2}{R}$. For small changes, the fractional change is $\frac{\Delta P}{P} = 2\frac{\Delta V}{V}$. The percentage decrease in power will be $2 \times 2.5\% = 5\%$.
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