Rankers Physics

Measuring Devices ( Galvanometer, Voltmeter and Ammeter & Meter Bridge ): Practice Problem & Solution

The resistance of each arm of the Wheatstone bridge is $10\text{ ohm}$. A resistance of $10\text{ ohm}$ is connected in series with galvanometer then the equivalent resistance across the battery will be: (2001)
$10\text{ ohm}$
$15\text{ ohm}$
$20\text{ ohm}$
$40\text{ ohm}$

Solution Explained:

To solve this problem, we apply the core principles of Measuring Devices ( Galvanometer, Voltmeter and Ammeter & Meter Bridge ). Understanding the underlying formula is key to arriving at the correct answer below:

The bridge has equal resistance ($10\text{ ohm}$) in all four arms, so it is balanced.nBecause it is balanced, the current through the galvanometer branch is zero, making its total resistance irrelevant.nThe equivalent resistance of the circuit is $\frac{(10+10) \times (10+10)}{(10+10) + (10+10)} = 10\text{ ohm}$.

Leave a Reply

Your email address will not be published. Required fields are marked *