Rankers Physics

Combination of Resistors: Practice Problem & Solution

Three resistances each of $4 \Omega$ are connected to form a triangle. The resistance between any two terminals is (1993)
$12 \Omega$
$2 \Omega$
$6 \Omega$
$8/3 \Omega$

Solution Explained:

To solve this problem, we apply the core principles of Combination of Resistors. Understanding the underlying formula is key to arriving at the correct answer below:

Between any two terminals of the triangle, two $4 \Omega$ resistors are in series, giving $8 \Omega$. This combination is in parallel with the third $4 \Omega$ resistor. Equivalent resistance $R_{eq} = \frac{8 \times 4}{8 + 4} = \frac{32}{12} = 8/3 \Omega$.

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