Rankers Physics

Combination of Resistors: Practice Problem & Solution

A carbon resistor of $(47 \pm 4.7)\text{ k}\Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be (2018)
Yellow - Green - Violet - Gold
Yellow - Violet - Orange - Silver
Violet - Yellow - Orange - Silver
Green - Orange - Violet - Gold

Solution Explained:

To solve this problem, we apply the core principles of Combination of Resistors. Understanding the underlying formula is key to arriving at the correct answer below:

$R = 47 \times 10^3\ \Omega \pm 10\%$.
First digit 4 $\rightarrow$ Yellow, second digit 7 $\rightarrow$ Violet, multiplier $10^3 \rightarrow$ Orange, tolerance $10\% \rightarrow$ Silver.
Sequence: Yellow - Violet - Orange - Silver.

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