Combination of Batteries: Practice Problem & Solution
A car battery of emf $12 \text{ V}$ and internal resistance $5 \times 10^{-2} \Omega$ receives a current of $60 \text{ A}$ from external source, then terminal voltage of battery is: (2000)
Solution Explained:
To solve this problem, we apply the core principles of Combination of Batteries. Understanding the underlying formula is key to arriving at the correct answer below:
During charging, current is forced into the positive terminal, so terminal voltage $V = E + Ir$. Substituting the values, $V = 12 + (60 \times 5 \times 10^{-2}) = 12 + 3 = 15 \text{ V}$.
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