Tangential Acceleration in Circular Motion – Rankers Physics

Kinematics of Circular Motion: Practice Problem & Solution

A particle of mass $10 \text{ g}$ moves along a circle of radius $6.4 text{ cm}$ with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to $8 \times 10^{-4} \text{ J}$ by the end of the second revolution after the beginning of the motion? (2016-I)
$0.1 \text{ m/s}^2$
$0.15 \text{ m/s}^2$
$0.18 \text{ m/s}^2$
$0.2 \text{ m/s}^2$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Kinematics of Circular Motion. Understanding the underlying formula is key to arriving at the correct answer below:

Work done by tangential force $W = (ma_t)s = \Delta K$, where distance $s = 4\pi r = 4 \times \pi \times 0.064 \text{ m}$. Substituting values gives $a_t = 0.1 \text{ m/s}^2$.

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Similar Practice Questions

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1. Assertion (A): A particle moving at constant speed and constant magnitude of radial acceleration must be undergoing uniform circular motion. Reason (R): In uniform circular motion speed cannot change as there is no tangential acceleration.  
2. A wheel having diameter of 3 m starts from rest and accelerates uniformly to an angular velocity of 210 rpm in 5 seconds. Angular acceleration of the wheel is :
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