Safe Turn and Centripetal Force – Rankers Physics

Dynamics of Circular Motion: Practice Problem & Solution

Assertion (A): During a safe turn, with constant speed the value of centripetal force should be less than or equal to the limiting frictional force. Reason (R): The centripetal force is provided by the frictional force between the tyre and the road.
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Dynamics of Circular Motion. Understanding the underlying formula is key to arriving at the correct answer below:

For a vehicle to take a safe turn on a flat road, the required centripetal force \( (mv^2/r) \) must be provided by the static frictional force between the tires and the road. This frictional force has a limiting maximum value \( f_{s,max} = \mu_s N \). Therefore, for a safe turn, the centripetal force must be less than or equal to this limiting frictional force.

Both (A) and (R) are true, and (R) correctly explains (A).

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