Rankers Physics

Calculation of Center of Mass: Practice Problem & Solution

The centre of mass of three particles of masses 1 kg, 2 kg and 3 kg is at (3, 3, 3) with reference to a fixed coordinate system. Where should a fourth particle of mass 4 kg be placed so that the centre of mass of the system of all particles shifts to the point (1, 1, 1)
(–1, –1, –1)
(–2, –2, –2)
(2, 2, 2)
(–3, –3, –3)

Solution Explained:

To solve this problem, we apply the core principles of Calculation of Center of Mass. Understanding the underlying formula is key to arriving at the correct answer below:

Center of mass of 1 kg, 2 kg and 3 kg is at (3, 3, 3) so, 6kg can be assumed to present at (3, 3, 3). 

Assume 4 kg is placed at (x,y,z) Center of mass is at (1,1,1)

1= (4x+6×3)/10

x=-2

similarly y=-2 and z=-2

COM(-2,-2,-2) 

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