Alternating Current: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:

Current in a series LCR circuit is maximum at resonance, where $X_L = X_C$.
This gives $\omega L = \frac{1}{\omega C} \implies L = \frac{1}{\omega^2 C}$.
Substituting the given values: $L = \frac{1}{(1000)^2 \times 10 \times 10^{-6}} = \frac{1}{10^6 \times 10^{-5}} = \frac{1}{10} H$.
Therefore, $L = 0.1 H = 100 mH$.