Alternating Current: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:

Capacitive reactance is $X_C = \frac{1}{\omega C} = \frac{1}{2\pi f C}$. RMS current is given by $I_{rms} = \frac{V_{rms}}{X_C} = V_{rms} \times 2\pi f C$. Substituting the values: $I_{rms} = 200 \times 2\pi \times 50 \times 40 \times 10^{-6} = 0.8\pi \approx 2.51 A \approx 2.5 A$.