Rankers Physics
Topic: Laws of Motion
Subtopic: Linear Momentum and Second Law of Motion

A body of mass 1 kg moving on a smooth horizontal surface with velocity 5m/s is to be brought to rest in 5 sec. How much force need to be applied :
25N
10N
5N
1N

Solution:

Force is defined as rate of change of momentum ie. F= dP/dt= change in momentum / time

Here Force = (mv-mu)/t= m(v-u)/t= 1 kg (0- 5)/ 5 = 1 N

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