Rankers Physics

Linear Momentum and Second Law of Motion: Practice Problem & Solution

A body of mass 1 kg moving on a smooth horizontal surface with velocity 5m/s is to be brought to rest in 5 sec. How much force need to be applied :
25N
10N
5N
1N

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Linear Momentum and Second Law of Motion. Understanding the underlying formula is key to arriving at the correct answer below:

Force is defined as rate of change of momentum ie. F= dP/dt= change in momentum / time

Here Force = (mv-mu)/t= m(v-u)/t= 1 kg (0- 5)/ 5 = 1 N

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. A hammer of man 1 kg moving with a speed of 6 m/sec strikes a wall and comes to rest in 0.1 sec find average retarding force that stops the hammer :
2. A particle of mass \( m \) is projected with velocity \( v \) making an angle of \( 45^{\circ} \) with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be: (2008)
3. The position-time graph of a particle of mass 2 kg moving along x-axis is as shown in the figure. The magnitude of impulse on the particle at t = 2 s is    
4. Acceleration of the block is :
5. A projectile is thrown at a speed of \(100\text{ m/s}\) at an angle of \(37^\circ\) above the horizontal. At the highest point the projectile breaks into two parts of mass ratio \(1 : 3\), the smaller coming to rest. Find the speed of the second piece.