Position-Time Graph in Uniformly Accelerated Motion – Rankers Physics

Graphs of Motion: Practice Problem & Solution

Assertion (A): For uniformly accelerated motion along straight line, the position versus time graph is a straight line. Reason (R): For uniformly accelerated motion the position in equal intervals of time changes by same amount.  
(1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
(2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(3) (A) is true but (R) is false
(4) Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Graphs of Motion. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is false.


For uniformly accelerated motion, position \( x \) is related to time \( t \) by \( x = x_0 + v_0 t + \frac{1}{2} a t^2 \). This is a parabolic equation, so the position-time graph is a parabola, not a straight line.


Reason (R) is false. In uniformly accelerated motion, velocity changes by equal amounts in equal time intervals, but position does not. Position changes by increasing amounts (if starting from rest).


Therefore, both the Assertion and the Reason are false.

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