Equations of Motion: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Equations of Motion. Understanding the underlying formula is key to arriving at the correct answer below:

Both maximum height \(H = \frac{u^2 \sin^2\theta}{2g}\) and time of flight \(T = \frac{2u \sin\theta}{g}\) are proportional to velocity \(u\). Since particle B has a larger velocity, both values are greater for B.