Solution:
\[ K.E= \frac{1}{2}K\left(A^{2}-x^{2} \right) \]
\[ P.E= \frac{1}{2}Kx^{2} \]
\[ \frac{1}{2}K\left(A^{2}-x^{2} \right)= \frac{1}{2}Kx^{2} \]
\[ x= A/\sqrt{2} \]
A particle is executing S.H.M., If its P.E. & K.E. is equal then the ratio of displacement &
amplitude will be :
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