Solution:
The maximum possible efficiency (Carnot efficiency) is \(eta_{\text{max}} = 1 - \frac{T_L}{T_H} = 1 - \frac{300}{600} = 50\%\). Practical heat engines have efficiency less than or equal to 50%, so 50%, 35%, and 25% are all possible values.
The maximum possible efficiency (Carnot efficiency) is \(eta_{\text{max}} = 1 - \frac{T_L}{T_H} = 1 - \frac{300}{600} = 50\%\). Practical heat engines have efficiency less than or equal to 50%, so 50%, 35%, and 25% are all possible values.
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