Solution:
Total K.E. per molecule is \(\frac{f}{2}k_B T\). For monoatomic Argon, \(f=3\), and for diatomic Oxygen, \(f=5\). At equal temperature, the ratio of K.E. is \(3:5\).
The ratio of total K.E of a molecule of Argon and Oxygen gas at 27°C is equal to:
Leave a Reply