Acceleration of a Particle in Circular Motion – Rankers Physics

Uniform Circular Motion: Practice Problem & Solution

A particle moves in a circle of radius \(10\text{ cm}\) with constant speed and time period \(\pi\text{ s}\). The acceleration of the particle is :
\(10\text{ cm/s}^2\)
\(20\text{ cm/s}^2\)
\(40\text{ cm/s}^2\)
\(50\text{ cm/s}^2\)

Solution Explained:

To solve this problem, we apply the core principles of Uniform Circular Motion. Understanding the underlying formula is key to arriving at the correct answer below:

The angular frequency is \(\omega = \frac{2\pi}{T} = \frac{2\pi}{\pi} = 2\text{ rad/s}\). The centripetal acceleration is \(a = \omega^2 R = 2^2 \times 10 = 40\text{ cm/s}^2\).

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