Ratio of Momenta for Equal Kinetic Energies – Rankers Physics

Kinetic Energy and Momentum: Practice Problem & Solution

Two masses \( 4m \) and \( 9m \) move with equal kinetic energy. The ratio of the magnitude of their momenta is:
\( 4 : 9 \)
\( 2 : 3 \)
\( 9 : 4 \)
\( 3 : 2 \)

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Kinetic Energy and Momentum. Understanding the underlying formula is key to arriving at the correct answer below:

Since kinetic energy \( K \) is the same for both masses, the momentum is proportional to the square root of the mass, \( p = \sqrt{2mK} \). Thus, the ratio of their momenta is \( \frac{p_1}{p_2} = \sqrt{\frac{4m}{9m}} = \frac{2}{3} \).

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