Solution:
Displacement current is given by \(I_d = C \frac{dV}{dt}\). Substituting the values: \(2 \times 10^{-3} = 4 \times 10^{-6} \frac{dV}{dt} ⇒ \frac{dV}{dt} = 500\text{ V/s}\).
To produce an instantaneous displacement current of 2 mA in the space between the parallel plates of a capacitor of capacitance 4 \(\mu\)F, the rate of change of applied variable potential difference \(\left(\frac{dV}{dt}\right)\) must be
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