Solution:
Acceleration of the blocks in both the case will be F/3m.
N1= m.a
N2= 2m.a
so N1/N2= 1/2
Two blocks are in contact on a frictionless table. One has mass m and the other 2 m. A force F is applied on 2 m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of force of contact between the two blocks will be:
Leave a Reply