Rankers Physics
Topic: Modern Physics
Subtopic: Nucleus

If the energy released in the fission of one nucleus is 200 MeV. Then the number of nuclei required per second in a power plant of 16 kW will be :
\[0.5\times 10^{14}\]
\[0.5\times 10^{12}\]
\[5\times 10^{12}\]
\[5\times 10^{14}\]

No solution provided for this question.

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