Rankers Physics

Nucleus: Practice Problem & Solution

The binding energy of deuteron is 2.2 MeV and that of $^4_2He$ is 28 MeV. If two deuteron are fused to form one $^4_2He$ then the energy released is: (2006)
21.6 MeV
23.6 MeV
17.2 MeV
28.2 MeV

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

Energy released $Q = \text{Binding Energy of Product} - \text{Total Binding Energy of Reactants}$. $Q = 28 - (2.2 + 2.2) = 28 - 4.4 = 23.6$ MeV.

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