Nucleus: Practice Problem & Solution
The nuclei $ _{6}C^{13} $ and $ _{7}N^{14} $ can be described as (1990)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
The number of neutrons in $ _{6}C^{13} $ is $ 13 - 6 = 7 $. The number of neutrons in $ _{7}N^{14} $ is $ 14 - 7 = 7 $. Nuclei with the same number of neutrons are called isotones.
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