Atomic Structure: Practice Problem & Solution
Ionisation potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr's theory, the spectral lines emitted by hydrogen will be: (2006)
Solution Explained:
To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:
Initial energy is $-13.6 eV$. After absorbing $12.1 eV$, the final energy is $-13.6 + 12.1 = -1.5 eV$. This corresponds to the $n=3$ state (since $-13.6/3^2 \approx -1.51 eV$). Number of spectral lines emitted upon returning to ground state is $\frac{3(3-1)}{2} = 3$.
Leave a Reply