Rankers Physics

Atomic Structure: Practice Problem & Solution

The total energy of an electron in the $n^{th}$ stationary orbit of the hydrogen atom can be obtained by. (2020-Covid)
$E_n = -\frac{13.6}{n^2} eV$
$E_n = -\frac{1.36}{n^2} eV$
$E_n = -13.6 \times n^2 eV$
$E_n = \frac{13.6}{n^2} eV$

Solution Explained:

To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:

According to Bohr's theory, the total energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by the formula $E_n = -\frac{13.6}{n^2} eV$.

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