Rankers Physics

Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

The wavelength of a $1 keV$ photon is $1.24 \times 10^{-9} m$. What is the frequency of $1 MeV$ photon? (1991)
$1.24 \times 10^{15}$
$2.4 \times 10^{20}$
$1.24 \times 10^{18}$
$2.4 \times 10^{23}$

Solution Explained:

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

Energy $E = 1 MeV = 10^6 eV$. In joules, $E = 10^6 \times 1.6 \times 10^{-19} = 1.6 \times 10^{-13} J$. Frequency $\nu = \frac{E}{h} = \frac{1.6 \times 10^{-13}}{6.63 \times 10^{-34}} \approx 2.4 \times 10^{20} Hz$.

Leave a Reply

Your email address will not be published. Required fields are marked *