Rankers Physics

Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is (c being velocity of light) (2016-I)
$\frac{1}{c} \left(\frac{E}{2m}\right)^{\frac{1}{2}}$
$\left(\frac{E}{2m}\right)^{\frac{1}{2}}$
$c(2mE)^{\frac{1}{2}}$
$\frac{1}{c} \left(\frac{2m}{E}\right)^{\frac{1}{2}}$

No solution provided for this question.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. The potential difference that must be applied to stop the fastest moving photoelectrons emitted by a metal surface, having work function \(4.5\text{ eV}\), when ultraviolet light of \(2000A^\circ\) falls on it, will be
2. An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) : ($m_e = 9 \times 10^{-31} kg$) (2019)
3. The nucleus $_{6}C^{12}$ absorbs an energetic neutron and emits a beta-particle ($\beta$). The resulting nucleus is (1990)
4. In the following question, a statement of Assertion (A) is followed by a statement of Reason (R). Assertion (A): On increasing intensity of light, more number of photoelectrons are emitted. Reason (R): The number of electrons emitted does not depend on intensity of incident radiations  
5. In a Rutherford scattering experiment, when a projectile of charge $z_1$ and mass $M_1$ approaches a target nucleus of charge $z_2$ and mass $M_2$, the distance of closest approach is $r_0$. The energy of the projectile is (2009)