Bar Magnet: Practice Problem & Solution
A circular loop of area $0.01 \text{ m}^2$ carrying a current of $10 text{ A}$, is held perpendicular to a magnetic field of intensity $0.1 \text{ T}$. The torque acting on the loop is (1994)
Solution Explained:
To solve this problem, we apply the core principles of Bar Magnet. Understanding the underlying formula is key to arriving at the correct answer below:
The torque on a current loop is given by $\tau = M B sin \theta$. Since the loop is held perpendicular to the magnetic field, the area vector is parallel to the field, making $\theta = 0^\circ$ and torque zero.
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