Force Acting on Moving Charges: Practice Problem & Solution
An electron is moving in a circular path under the influence of a transverse magnetic field of $3.57 \times 10^{-2}\text{ T}$. If the value of $e/m$ is $1.76 \times 10^{11}\text{ C/kg}$, the frequency of revolution of the electron is: (2016 - II)
Solution Explained:
To solve this problem, we apply the core principles of Force Acting on Moving Charges. Understanding the underlying formula is key to arriving at the correct answer below:
The frequency of revolution is $f = \frac{eB}{2\pi m}$. Substituting values yields $f = \frac{1.76 \times 10^{11} \times 3.57 \times 10^{-2}}{2\pi} \approx 6.28\text{ MHz}$.
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