Rankers Physics

Power of Electrical Circuit: Practice Problem & Solution

If two bulbs, whose resistances are in the ratio of $1 : 2$ are connected in series, the power dissipated in them has the ratio of (1997)
$2 : 1$
$1 : 4$
$1 : 1$
$1 : 2$

Solution Explained:

To solve this problem, we apply the core principles of Power of Electrical Circuit. Understanding the underlying formula is key to arriving at the correct answer below:

In a series circuit, the current $I$ is the same through both bulbs. Since power $P = I^2 R$, the power dissipated is directly proportional to the resistance. Hence, the ratio is $1 : 2$.

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